Question

980 g vitriol de c=10% se neutralizeaza cu soda caustica de c=10%
a)ecuatia reactiei chimice
b)masa solutiei de soda caustica necesara neutalizarii
c)cantitatea de sare rezultata din reactie

Answer 1

vitriol ⇒ H2SO4

soda caustica ⇒ NaOH

a) H2SO4 + 2NaOH = Na2SO4 + 2H2O

b) Cp=md/ms*100=>md=Cp*ms/100=10*980/100=98g H2SO4

MH2SO4=98g/mol

MNaOH=40g/mol

98g H2SO4...............2*40g NaOH
98g.............................80g

Cp=md/ms*100=>ms=md*100/Cp=80*100/10=800g. sol NaOH

c) 98g H2SO4..................142 Na2SO4
98g.................................142g

MNa2SO4=142g/mol

n=m/M=142/142 = 1 mol sare Na2So4