Question

a)[-0,(3)]‐²=?
b) 3-²
c)(2/3)‐³
d)(-0,25)‐¹
e) (0,1)‐³
f)(-1/2)‐²
urgent,va rog
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Answer 1

a) 0,(3) = 1/3,

( -1/3)^-2 = 3^2 = 9.

b) 3^-2= 1/9.

c) (2/3)^-3 = (3/2)^3 = 27/8.

d) ( 0,25 )^-1 = ( -1/4)^-1 = -4

e) (0,1)^-3 = 10^3.

f) (-1/2)^-2 = (-2)^2 = 4

Answer 2

Răspuns:

a)

$[-0,(3)]^{-2} = [-\frac{3}{9}]^{-2} = (-\frac{1}{3})^{-2} =\frac{1}{(-\frac{1}{3})^{2}}=\frac{1}{\frac{1}{9}} = 1* \frac{9}{1} = \boxed{9}$

b)

$3^{-2}=\frac{1}{3^{2} } = \boxed{\frac{1}{9} }$

c)

$(\frac{2}{3})^{-2} =\frac{1}{(\frac{2}{3})^{2}} = \frac{1}{\frac{4}{9}}} = 1 * \frac{9}{4} =\boxed{\frac{9}{4} }$

d)

$(-0,25)^{-1} = \frac{1}{-0,25} = \boxed{-\frac{1}{0,25}}$

e)

$(0,1)^{-3} = \frac{1}{(0,1)^{3}} = \boxed{\frac{1}{0,001} }$

f)

$(-\frac{1}{2} )^{-2} = \frac{1}{(-\frac{1}{2} )^{2}} = \frac{1}{\frac{1}{4}} = 1 * \frac{4}{1} = \boxed{4}$