Matematică, întrebare adresată de Ionuțț96, 9 ani în urmă

A) [1,10(2) - 3 2\15] - (1 1\4 +2 1\8 -3 1\2) ;
B) 14\15 -[1,(6) - 3 1\6 +(9\10- 0,(3)] .
C) [2/3-0,1]-[1,0(6)-1,(3)-(-4/45)
D)[1,25+2,1(6)-0,125]-[4,(25)-0,(29)
VĂ ROG AM NEVOIE URGENT!

Răspunsuri la întrebare

Răspuns de finamihai
8
A) [1,10(2) - 3 2/15] - (1 1/4 +2 1/8 -3 1/2) 1,10(2)=(1102-110)/900=992/900=496/450=248/225
3 intregi 2/15=(3·15+2)/15=47/15
2intregi 1/8=17/8
3intregi1/2=7/2
(248/225-47/15)-(17/8-7/2)=
[(248-47·15)/225]-[(17-7·4)/8]=
[(248-705)/225]-[(17-28)/8]=
-457/225-(-11/8)=
-457/225+11/8=
(-457·8+11·225)/1800=(-3656+2475)/1800=-1181/1800=-0,656(1)

B) 14/15 -[1,(6) - 3 1/6 +(9/10- 0,(3)] 
1,(6)=(16-1)/9=15/9=5/3
3 intregi 1/6=19/6
0,(3)=3/9=1/3
14/15-[5/3-19/6+(9/10-1/3)]=
14/15-5/3+19/6-9/10+1/3=
14/15-9/10-4/3+19/6=
(14·2-9·3-4·10+19·5)/30=
(28-27-40+95)/30=56/30=28/15=1,8(6)

C) [2/3-0,1]-[1,0(6)-1,(3)-(-4/45)
0,1=1/10
1,0(6)=(106-10)/90=96/90=48/45=16/15
1,(3)=(13-1)/9=12/9=4/3
(2/3-1/10)-(16/15-4/3+4/45)=
2/3-1/10-16/15+4/3-4/45=
(2
·30-1·9-16·6-4·2)/90=
(60-9-96-8)/90=-53/90=-0,5(8)

D)[1,25+2,1(6)-0,125]-[4,(25)-0,(29)]
1,25=125/100=25/20=5/4
2,1(6)=(216-21)/90=195/90=39/18=13/6
0,125=125/1000=25/200=5/40=1/8
4,(25)=(425-4)/99=421/99
0,(29)=29/99
(5/4+13/6-1/8)-(421/99-29/99)=
[(5
·6+13·4-1·3)/24-392/99=
(30+52-3)/24-392/99=
79/24-392/99
(79·33-392·8)/792=
(2607-3136)/792=-529/792=-0,667(92)

Ionuțț96: Trebuiau transformate. Totusi mutumesc. Le.am rezolvat singură
Ionuțț96: Multumesc*
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