Question

A=1+2+2^2+2^3+.....+2^2015 si B=[32^63]^4X[(64)^7]^18.Aflati A+1;(A-B)^2015. Ma ajutati, va rog ?

Answer 1

Progresie geometrica de ratie q=2 si termeni 2016 deci avem
A= (2^2016  -  1) / (2-1) = 2^2016  -  1
B=  ((2^5)^63)^4  x  (((2^6))^7)^18 = 2^(5x63x4)  x 2^(6x7x18) = 2^1260 x 2^756 = 2^(1260+756) = 2^2016
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A+1 = 2^2016 = B
(A-B)^2015 = (2^2016  -  1  -  2^2016)^2015 = ( -1)^2015 = -1
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Succes in continuare!