Question

a)(1+2+3+4+...400):802
b)(6+12+18+...+312):(3+6+9+...+156)​

Answer 1

a) 1+2+...+400= (400x401):2= 100x802 (Suma lui Gauss)

Impartirea de la prima vine astfel:
(100x802):802=100

b) Dam factor comun in ambele paranteze, in prima 6 in a 2 a dam factor comun 3:

6x(1+2+3+...+52):3x(1+2+...+52)=
6 impartit la 3= 2

=> (2x (52x53):2) : (52x53):2=

= (52x53):(26x53)= 2