Question

a) (1+3×3²×3⁴) : (3⁷+1)=
b) (6²+2²-2⁰) : 13×3⁷:3⁶+3²=
va rog nu pot scrie tot raspundeti la intrebarea din poza va rog​

Answer 1

Răspuns:

a)(1+3^7):(3^7+1)=1

b)(6^2+2^2-1):13*3^1+3^2=(36+4-1):13*3+9=39:13*3+9=3*3+9=9+9=18

c)(4+2^4) :5=(4+16) :5=20:5=4

d)5^40:(33-28)^38=5^40:5^38=5^2=25

e)4+16:2-1-1=4+8-1-1=12-1-1=10

f)2*[2+3*(4+27-25) ]=2*(2+3*6)=2*(2+18)=2*20=40

g)(1+3^6:3^5+27):15=(3+27):15=30:15=2

Explicație pas cu pas:

a^x*a^y=a^x+y

a^0=1

0^a=1