Question

a) 10√1,44+√48-√2-6-5√0,16
                               √3


b)1    -    1
√7-2   √7+2

Answer 1

10√1,44+√48 - √2 - 6/√3 - 5√0,16 =
=10*1.2+4√3 - √2 - 6√3/3 - 5*0,4 =
=12+ 2√3 - √2 - 2 =
=10+ 2√3 - √2

am intalnit exercitiul si asa :
10√1,44+√48 - √12 - 6/√3 - 5√0,16 =
=10*1.2+4√3 - 2√3 - 6√3/3 - 5*0,4 =
=12+ 2√3 - 2√3 - 2 =
=10

b) 1/(√7-2)-1/(√7+2)=
=(√7+2-√7+2)/(√7-2)(√7+2)=
=4/(7-4)=
=4/3