Question

a×10-10×[362+10×(24+18:3)]=10×10
prin metoda mersului invers va rog.

Answer 1

a×10-10×[362+10×(24+6)]=100
a×10-10×(362+10×30)=100
a×10-10×(362+300)=100
a×10-10×662=100
a×10-6620=100
a×10=100+6620
a×10=6720
a=6720:10
a=672

Answer 2

a×10-10×[362+10×(24+18:3)]=100
B-10×[362+10×(24+6)]=100
B-10×[362+10×30]=100
B-10×(362+300)=100
B-10×662=100
B-6.620=100
B=6.620+100
B=6.720
a×10=6.720
a=6.720:10
a=672

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