Question

[(a+116:2)x3+4]x11=1991 rezolvarea?
(b:11-4):3-110:2=4 rezolvarea?

Answer 1

[(a+116:2)x3+4]x11=1991
(a+116:2)x3+4= 1991 : 11
(a+116:2)x3+4 = 181
(a+116:2)x3 = 181-4
(a+116:2)x3 = 177
a+116:2 = 177:3
a+116:2 = 59
a+58 = 59
a = 59-58
a=1

(b:11-4):3-110:2=4
(b:11-4):3-55=4
(b:11-4):3=4+55
(b:11-4):3=59
b:11-4=59x3
b:11-4=177
b:11=177+4
b:11=181
b=181x11
b=1991