Question

a) [123+2 la puterea 7x2 la puterea 2+2 la puterea 67 : 2 la puterea27] : [123+2 la puterea 14 : 2 la puterea 5+(2 la puterea 5) la puterea 8]

Answer 1

$[123+2^7 \cdot 2^2+2^6^7:2^2^7]:[123+2^1^4:2^5+(2^5)^8]= \\ =(123+2^{7+2}+2^{67-27}):(123+2^{14-5}+2^4^0)= \\ =(123+2^9+2^4^0):(123+2^9+2^4^0)=1$