Matematică, întrebare adresată de minunela, 9 ani în urmă

a) 13^6:13^5=
b)23^7:23^2:23=
c)(2^3)^5:2^10=
d) 11^50:11^45-11^5=
e)(3^2•5)^3:(3^6•5^3)=
f)4^12:2^23+9^15:3^29=
g) (3•3^2•3^3•3^200):9^103=
Ex4:
a) 4^25:4^23-3^23:3^21=
b) (14-11)^25:(23•20)^23=
c) (3^3)^8:(3^6-3^4)=
d) 24^3:6^3-4^23:4^20=
e)5^176•5^0•5^24:5^199=
f) 2^24:3^24-6^24=
g) (5^7+5^8+5^9):5^6=
h) (7^4+2•7^5+3•7^6):162=
Urgent dau coroniță


Betusca: ce inseamna ^ ca nu inteleg
minunela: 13la puterea a 6a
renatemambouko: la ex 4 pct b ceva e gresit scris
renatemambouko: si la f e ceva gresit, cred
minunela: da am greșit (14-11)^25:(23-20)^23=3^2=9 l-am rezolvat eu e bine
minunela: la f nu am greșit asa este

Răspunsuri la întrebare

Răspuns de renatemambouko
4
a) 13^6:13^5=13
b)23^7:23^2:23=
23^2
c)(2^3)^5:2^10=
2^15:2^10=2^5
d) 11^50:11^45-11^5=11^5-11^5=0
e)(3^2•5)^3:(3^6•5^3)=
(3^6•5^3):(3^6•5^3)=1
f)4^12:2^23+9^15:3^29=
2^24:2^23+3^30:3^29=2+3=5
g) (3•3^2•3^3•3^200):9^103=
3^206:3^206=1

Ex4:
a) 4^25:4^23-3^23:3^21=
4^2-3^2=16-9=7

c) (3^3)^8:(3^6-3^4)=
3^24:3^4(3^2-1)=3^20/8=3^20/2^3
d) 24^3:6^3-4^23:4^20=
4^3-4^3=0
e)5^176•5^0•5^24:5^199=
5^200•1:5^199=5
g) (5^7+5^8+5^9):5^6=5^7(1+5^1+5^2):5^6=5(1+5+25)=155
h) (7^4+2•7^5+3•7^6):162=
7^4(1+2•7^1+3•7^2):162=
=7^4(1+14+147):162=7^4×162:162=7^4













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