Question

A)2×3×4×5supra7×8×9×10÷1/42
B)0,2÷0(2)×11,(1)

Answer 1

A. $\frac{2*3*4*5}{7*8*9*10}:\frac{1}{42}= \frac{2}{7*12}:\frac{1}{42}= \frac{1}{42}:\frac{1}{42}= 1$

B. $0,2:0,(2)*11,(1)= \\ \\ 0,2= 0\frac{2}{10}= \frac{1}{5} \\ 0,(2)= 0\frac{2}{9}= \frac{2}{9} \\ 11,(1)=11\frac{1}{9}=\frac{100}{9} \\ \\ \frac{1}{5} :\frac{2}{9}*\frac{100}{9}= \\ \frac{9}{45}*\frac{45}{10}*\frac{100}{9}= \\ \frac{9}{10}*\frac{100}{9}=10$

\\weskizq