Question

a) (2+4+6+...+100) : 51 =
b ) (3+6+9+...+150) : 3 =
c ) (4+8+12+...+44) : 22 =
Pls ajutati-ma dau coronita urgent

Answer 1

sper că te-am ajutat

Answer 2

a) (2+4+6+...+100):51=2(1+2+3+...+50):51=(2*50*51/2):51=2*50/2=100/2=50

b) (3+6+9+...+150):3=3(1+2+3+...+50):3=50*51/2=2550/2=1275

c) (4+8+12+...+44):22=4(1+2+3+...+11):22=(4*11*12/2):22=(528/2):22=264:22=12

pentru calculul sumelor din paranteze s-a folosit formula lui Gauss