Question

A)2 intregi 2 pe 3-0,(3)
B)3 intregi 1 pe 3-1,(6)
C)4,1(3)-1 intreg 8 pe 15
D)5 intregi 1 pe 6-4,8(3)
VĂ ROG MULT!!!! =(

Answer 1

a) 2si 2/3-0,(3)=
(2×3+2)/3-3/9=
8/3-3/9=(3×8-3)/9=(24-3)/9=21/9=7/3

b) 3si1/3-1,(6)=
(3×3+1)/3-(16-1)/9=
10/3-15/9=10/3-5/3=5/3

c) 4,1(3)-1si 8/15=
(413-41)/90-(1×15+8)/15=
372/90-23/15=62/15-23/15=39/15=13/5

d) 5si1/6-4,8(3)=
(5×6+1)/6-(483-48)/90=
31/6-435/90=31/6-29/6=2/6=1/3

Succes!