Question

a= (2 la puterea 98 + 2 la puterea 99) ori (5 la puterea 99 + 5 la puterea 100)

Answer 1

1+2=3

1+5=6

2^98+2^99=2^98(1+2)

5^99+5^100=5^99 (1+5)=6*5^99=6*5*5^98

atunci

3*2^98 *6*5^99=3*6*5*2^98*5^98=90 *10^98=9*10^99 (scriere stiintifica 9exp99 sau 9e99)