Question

a=(2 supra 5√3-1supra √12+3supra√75)*√27

Answer 1

2/5√3 = 2√3/15
1/√12 = 1/2√3 = √3/6
3/√75 = 3/5√3 = 3√3/15 = √3/5
√27=3√3

A = (2√3/15 - √3/6 + √3/5) · 3√3
A = 6/5 - 3/2 + 9/5
Numitor comun 10
A=(12-15+18)/10
A=15/10
A=3/2

Answer 2

a=(2/5√3-1/√12+3/√75)*√27
a=(2√3/15 - √3/6 + √3/5)*3√3
a=6/5 - 3/2 + 9/5
a=(12-15+18)/10
a=15/10
a=3/2


OBS. Numitorul comun este 10.








„CLAUAND„