Question

a=2 supra radical din 3 +1 +4 - radical din 3 ; b= 2 supra radicaldin2+1 totul la patrat + 2+radical din 2 totul la patrat
Aflati media geometrica
Va rog muuult !

Answer 1

$a=\dfrac{2}{\sqrt3+1} +4 - \sqrt3 = \dfrac{2(\sqrt3 - 1)}{3-1} +4-\sqrt3 = \sqrt3-1+4-\sqrt3=3$


[tex] b = \dfrac{2}{(\sqrt2 + 1)^2} +(2+\sqrt2)^2 =\dfrac{2}{3+2\sqrt2}+4+4\sqrt2 +2 = \\\;\\ = \dfrac{2(3-2\sqrt2)}{9-8} +6+4\sqrt2= 6-4\sqrt2+6+4\sqrt2 =12[/tex]

$\it m_g =\sqrt{a \cdot b} =\sqrt{3\cdot12} =\sqrt{36} =6$