Question

a) 2 · (x + 1) = -7(x + 3) + 3(3x - 5) - 5;
b) -3 . (3x + 1) + 14 = 3(7x – 3) - 10;
c) 14+2. [3 – 2(x – 3)] : 2 = 37;
d) 4- {6-[-3+(-3) + (-5 - x) - 7] -9} = 1;
e)5 (7x - 1) + 2(x + 1) = -7(x+3) + 3(3x - 5)+43.​

Answer 1

Răspuns:

$a)2(x + 1) = - 7( x + 3) + 3(3x - 5) - 5 \\ 2x + 2 = - 7x - 21 + 9x - 15 - 5 \\ 2x + 7x - 9x = - 21 - 15 - 5 - 2 \\ 9x - 9x = - 43 \\0 = - 43 \: \: \: \: \: \: \: \: \: \\ solutia \: este \: multime \: vida$

$b) - 3(3x + 1) + 14 = 3(7x - 3) - 10 \\ - 9x - 3 + 14 = 21x - 9 - 10 \\ - 9x - 21x = - 9 - 10 + 3 - 14 \\ - 30x = - 30 \\ x = - 30 \div ( - 30) \\ x = 1$

$c)14 + 2(3 - 2(x - 3)) \div 2 = 37 \\ 14 + 6 - 2x + 6 \div 2 = 37 \\ 20 - 2x + 3 = 37 \\ - 2x = 37 - 20 - 3 \\ - 2x = 14 \\ x = 14 \div ( - 2) \\ x = - 7$

$d)4 - (6 - ( - 3 + ( - 3) + ( - 5 - x) - 7) - 9) = 1 \\ 4 - (6 - ( - 3 - 3 - 5 - x - 7) - 9) = 1 \\ 4 - (6 + 18 + x - 9) = 1 \\ 4 - ( - 15 + x) = 1 \\ 4 - 15 - x = 1 \\ - 11 - x = 1 \\ - x = 1 + 11 \\ - x = 12 \\ x = - 12$

$e)5(7x - 1) + 2(x + 1) = - 7(x + 3) + 3(3x - 5) + 43 \\ 35x - 5 + 2x + 2 = - 7x - 21 + 9x - 15 + 43 \\ 35x + 2x + 7x - 9x = - 21 - 15 + 43 + 5 - 2 \\ 35x = 10 \\ x = 10 \div 35 \\ x = \frac{2}{7}$