Question

a) 2^x=32
b)2^x+^2=8
c)2^x×3^x=36

urgent va rog

Answer 1

a) $2^{x}=32 => 2^{x}=2^{5} => x=5$;

b) $2^{x+2}=8 => 2^{x+2}=2^{3} => x=1$;

c) $2^{x}$·$3^{x}=36 => 2^{x}$·$3^{x}$=2²·3² $=> x=2$.