Question

a 2016 la puterea 0-1 la puterea 2016+2la puterea 2=? b 2 la a 6 impartit la 4 la 3+ 3 la 5 la 0 -0 la 2016=? cu explicare dau coroana

Answer 1

${2016}^{0} - {1}^{2016} + {2}^{2} = 1 - 1 + 4 = 0 + 4 = 4$
${2}^{6} \div {4}^{3} + ( {3}^{5}) ^{0} - {0}^{2016} = {2}^{6} \div ( {2}^{2} ) ^{3} + 1 - 0 = 1 + 1 - 0 = 2$

Answer 2

2016^0-1^2016+2^2=1-1+4=4
2^6:4^3+3^5^0-0^2016=2^6:(2^2)^3+3^1-0=2^6:2^6+3-0=1+3=4