Question

A=√20²+15² [ambele numere sunt sub radical]
B=√1681
C=√2⁴*3² [ambele numere sunt sub radical]
Aflati A-B-C

Answer 1

$A= \sqrt{ 20^{2}+ 15^{2} } = \sqrt{400+225} = \sqrt{625} =25$
$B= \sqrt{1681} = \sqrt{ 41^{2} } =41$
$C= \sqrt{ 2^{4}* 3^{2}} =4*3=12$
A-B-C=25-41-12=-28