Question

a) 2³ +2² +2²⁰⁰⁰ • (3²-2³-5⁰)
va rog grabiti-va​

Answer 1

Răspuns: $\bf \red{\underline{12}}$

Explicație pas cu pas:

$\bf 2^3 +2^2 +2^{2000}\cdot \Big(3^2-2^3-5^0\Big)=$

$\bf 2^3 +2^2 +2^{2000}\cdot \Big(9-8-1\Big)=$

$\bf 2^3 +2^2 +2^{2000}\cdot 0=$

$\bf 2^3 +2^2 +0=8+4=\red{\underline{12}}$

$\it~~$

$\purple{\bf \star~\underline{Formule~pentru~puteri}:}$

$\bf a^{0} = 1;$

$\bf (a^{n})^{m} = a^{n \cdot m};$

$\bf a^{n}\cdot a^{m} =a^{n+m};$

$\bf a^{n}: a^{m} =a^{n-m}$

==pav38==

Baftă multă !