Question

A=(25^3)^9÷(4^2+3^2)^26-(2017^0+0^2017+1^2017)^4

Answer 1

A= 25 la puterea 27 impartit la 24 la puterea 26- (1+0+1) la puterea a 4

A= 25-2 la puterea 4

A= 25-16=9

Sper ca te-am ajutat

Answer 2

$A=\frac{\left(25^3\right)^9}{\left(4^2+3^2\right)^{26}}-\left(2017^0+0^{2017}+1^{2017}\right)^4=\frac{\left(25^3\right)^9}{\left(4^2+3^2\right)^{26}}-\left(1^{2017}+0+2017^0\right)^4=\frac{\left(25^3\right)^9}{\left(4^2+3^2\right)^{26}}-\left(0+1+2017^0\right)^4=\frac{\left(25^3\right)^9}{\left(4^2+3^2\right)^{26}}-\left(1+0+1\right)^4=\frac{\left(25^3\right)^9}{\left(4^2+3^2\right)^{26}}-\left(1+0+1\right)^4=25-2^4==25-16=9$