Question

[(a+260:2)×3+4]×5=1985

dau coroana

Answer 1

Salutare!:)

[(a+260:2)×3+4]×5=1985

[(a+130)×3+4]=1985:5

[(a+130)×3+4]=397

[(a+130)x3]=397-4

(a+130)×3=393

a+130=393:3

a+130=131

a=131-130

a=1

Answer 2

Explicație pas cu pas:

ღSalutare!ღ

[(a+260:2)×3+4]×5=1985

(a+260:2)×3+4=1985:5

(a+130)×3+4=397

(a+130)×3=397-4

(a+130)×3=393

a+130=393:3

a+130=131

a=131-130

a=1✅

Verificare:

[(1+260:2)×3+4]×5=1985

[(1+130)×3+4]×5=1985

(131×3+4)×5=1985

(393+4)×5=1985

397×5=1985

1985=1985 Corect!:)

Succes!;)