Question

a) (2a+3b)^2 b)(2x^2+1)^2 c)(6x^3y^2+5x^2y)^2

Answer 1

a)

(2a+3b)²=

(2a)²+2•2a•3b+(3b)²=

4a+12ab+9b²

b)

(2x²+1)²=

(2x²)²+2•2x²•1+1²=

4x⁴+4x²+1

c)

(6x³y²+5x²y)²=

(6x³y²)²+2•6x³y²•5x²y+(5x²y)²=

${36x}^{6} {y}^{4} + {60x}^{5} {y}^{3} + {25x}^{4} {y}^{2}$