a+2b+3c=41. 5a+4b+2c=55. a+b+c=?
cocirmariadenis:
5a+4b+2c=55 nu ai cumva 3 c ?
Sunt sigura ca e 3 c si nu 2 c ! Antonio , imi raspunzi ?
Sigur e asa, altfel problema nu se poate rezolva cu datele incluse.
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Răspunsuri la întrebare
Răspuns de
8
a + 2 b + 3 c = 41
5 a + 4 b + 3 c = 55
___________________ → le adun
6 a + 6 b + 6 c = 96 → il dau factor comun pe 6
6 × ( a + b + c ) = 96
a + b + c = 96 : 6
a + b + c = 16 → suma celor trei numere
5 a + 4 b + 3 c = 55
___________________ → le adun
6 a + 6 b + 6 c = 96 → il dau factor comun pe 6
6 × ( a + b + c ) = 96
a + b + c = 96 : 6
a + b + c = 16 → suma celor trei numere
Așa este ms!!
Cu drag !
Multumesc pentru coronita !
Răspuns de
1
a+2b+3c=41 | + 5*(a+2b+3c)=41*5⇒
5a+4b+2c=55 5a+10b+15c=205
----------------------
6a+6b+5c=96 +
5a+10b+15c=205 |- 6a+6b+5c=96 |+
5a+4b + 2c= 55 6b+13c=150
------------------------- ----------------------
/ 6b +13c=150 6a+12b+18c=246
6a+12b+18c=246 |- a+8b+16c=191 |-
5a+ 4b+ 2c=55 a+2b+ 3c=41
-------------------------- --------------------------
a+ 8b + 16c=191 / 6b+15c=150
6b+15c=150⇒3*(2b+5c)=3*50⇒2b+5c=50
6a+4b+(2b+5c)=96⇒6a+4b+50=96⇒6a+4b=46⇒2*(3a+2b)=2*23⇒
3a+2b=23
5a+4b+2c=55⇒2a+(3a+2b)+2b+2c=55⇒2a+23+2b+2c=55⇒
2a+2b+2c+23=55⇒2a+2b+2b=55-23⇒
2a+2b+2c=32 ⇒ 2*(a+b+c)=32 ⇒ a+b+c=32/2⇒
a+b+c=16
5a+4b+2c=55 5a+10b+15c=205
----------------------
6a+6b+5c=96 +
5a+10b+15c=205 |- 6a+6b+5c=96 |+
5a+4b + 2c= 55 6b+13c=150
------------------------- ----------------------
/ 6b +13c=150 6a+12b+18c=246
6a+12b+18c=246 |- a+8b+16c=191 |-
5a+ 4b+ 2c=55 a+2b+ 3c=41
-------------------------- --------------------------
a+ 8b + 16c=191 / 6b+15c=150
6b+15c=150⇒3*(2b+5c)=3*50⇒2b+5c=50
6a+4b+(2b+5c)=96⇒6a+4b+50=96⇒6a+4b=46⇒2*(3a+2b)=2*23⇒
3a+2b=23
5a+4b+2c=55⇒2a+(3a+2b)+2b+2c=55⇒2a+23+2b+2c=55⇒
2a+2b+2c+23=55⇒2a+2b+2b=55-23⇒
2a+2b+2c=32 ⇒ 2*(a+b+c)=32 ⇒ a+b+c=32/2⇒
a+b+c=16
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