Question

a)√3*(2√108-5√75)+√2*(√72-3√242)=
b)-√2*(3√128-4√450)+√3*(√147-2√243)=

Answer 1

a)√3*(2√108-5√75)+√2*(√72-3√242)=
=√3*(12√3-25√3)+√2*(6√2-33√2)=
=√3*(-13√3)+√2*(-27√2)=
=-13*3-27*2=
=-39-54=-93

b)-√2*(3√128-4√450)+√3*(√147-2√243)= =-√2*(24√2-60√2)+√3*(7√3-18√3)=
=-√2*(-36√2)+√3*(-11√3)=
=36*2-11*3=
=72-33=39