Question

a) [(3^2)^5:3^7-3^0-3^2]•4:34+2^2
b) [132+2^7•2^2+2^67:2^27]:[132+2^14:2^5+(2^5)^8]

Answer 1

   
[tex]a) ~~ \\ ~ [(3^2)^5:3^7-3^0-3^2] \times 4:34+2^2 = \\ = [3^{2\times 5}:3^7-3^0-3^2] \times 4:34+2^2 = \\ = [3^{10}:3^7-3^0-3^2] \times 4:34+2^2 = \\ = [3^{10-7}-3^0-3^2] \times 4:34+2^2 = \\ = [3^3-3^0-3^2] \times 4:34+2^2 = \\ = [27-1-9] \times 4:34+4 = \\ = 17 \times 4:34+4 = 68:34 +4 = 2 + 4 = \boxed{6}[/tex]


[tex]b) \displaystyle \\ ~ [132+2^7 \times 2^2+2^{67}:2^{27}]:[132+2^{14}:2^5+(2^5)^8]= \\~ [132+2^{7+2}+2^{67-27}]:[132+2^{14-5}+2^{5 \times 8}]= \\~ [132+2^{9}+2^{40}]:[132+2^{9}+2^{40}]= \frac{132+2^{9}+2^{40}}{132+2^{9}+2^{40}}=\boxed{1} [/tex]