Question

a) [3/20-0.(3)]:[9/40+0.05-0.(1)] =
b) [0.8(3)+3/4]:[0.69(4)-0.625+9/4] =
VA ROG AJUTATIMA Imi trebuie si rezolvarile plz!!!!!!!

Answer 1

A)0,(3)=3/9=simplif.cu 3=1/30,05=5/100=simplif.cu 5=1/20
0,(1)=1/9
[3/20-0.(3)]:[9/40+0.05-0.(1)] =(3/20-1/3):(9/40+1/20-1/9)=
[(3-1·20)/3]:[(9·9+1·18-1·40)/360]=
(-17/3):[(81+18-40)/360]=
(-17/3):59/360=
(-17/3)·360/59=
(-17/1)·120/59=-2040/59

b)0,8(3)=(83-8)/90=75/90=simplif.cu 5=15/18=5/6
0,69(4)=(694-69)/900=625/900=125/180=25/36
0,625=625/1000=125/200=25/40=5/8
 [0.8(3)+3/4]:[0.69(4)-0.625+9/4] =
(5/6+3/4):(25/36-5/8+9/4)=
[(5·4+3·6)/24]:[(25·2-5·9+9·18)/72]=
[(20+18)/24]:[(50-45+162)/72]=
38/24:167/72=
19/12·72/167=simplif ce se poate=
19/1·6/167=114/167