Question

a)3,(4)+0,(8)=
b)(0,3+2 supra 5 )+(5-2 1 supra 5 )
rezultatele ca fracție ireductibilă,plss
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Answer 1

Răspuns:

$3.(4) + 0.(8) = \frac{34 - 3}{9} + \frac{8}{9} \\ \frac{31}{9} + \frac{8}{9} = \frac{39}{9} = \frac{13}{3}$

$(0.3 + \frac{2}{5} ) + (5 - \frac{21}{5} ) =( \frac{3}{10} + \frac{2}{5} ) + (5 - \frac{21}{5}) \\ (\frac{3}{10} + \frac{4}{10} ) + ( \frac{25}{5} - \frac{21}{5} ) = \frac{7}{10} + \frac{4}{5} = \frac{7}{10} + \frac{8}{10} = \frac{15}{10} = \frac{3}{2}$