Question

a) (3√5+√2)^2-3√2*√20+(5√2-√5)^2+2√2*√125
b) (√6-2)^2+2√2*√12+(2√2-1)^2-√32+(√7+√3)^2+(√5-2)(√5-2)(√5+2)
c) (2√2-√3)(2√2+√3)-2(√3-1)^2+(4-2√3)^2-(3-2√3)^2
Repede!!

Answer 1

a) (3√5+√2)²-3√2*√20+(5√2-√5)²+2√2*√125=
=45+6√10+2-3√2*2√5+50-10√10+5+2√2*5√5=
=47+6√10-6√10+55-10√10+10√10=
=47+55=102



b) (√6-2)²+2√2*√12+(2√2-1)²-√32+(√7+√3)²+(√5-2)(√5-2)(√5+2)=
=6-4√6+4+2√2*2√3+8-4√2+1-4√2+7+2√21+3+(√5-2)(5-4)=
=10-4√6+4√6+9-4√2-4√2+7+2√21+3+√5-2=
=27-8√2+2√21+√5


c) (2√2-√3)(2√2+√3)-2(√3-1)²+(4-2√3)²-(3-2√3)²=
=8-3-2(3-2√3+1)+(16-16√3+12)-(9-12√3+12)=
=5-6+4√3-2+16-16√3+12-9+12√3-12=
=5-6-2+16-9=
=4