Question

A=(3-√7) × √ lung din 16+6√7
b=(4+2√3)(√3-1)²
a comparat cu b ?

Answer 1

$a=(3- \sqrt{7} )* \sqrt{16+6 \sqrt{7} } \\a=(3- \sqrt{7} )*(3+ \sqrt{7} )\\a=9-7\\a=2\\b=(4+2 \sqrt{3} ) ( \sqrt{3} -1)^{2} \\b=(4+2 \sqrt{3} )(4-2 \sqrt{3} )\\b=16-12 \\ b=4$