Question

a ^ 3 + b ^ 3 >= ab(a + b)​

Answer 1

Răspuns:

Explicație pas cu pas:

are sens pt a+b>0

(a+b)(a²-ab+b²)≥ab(a + b)​

simplificam cu a+b>0, sensul inecuatiei se pasteaza

(a²-ab+b²)≥ab

(a²-2ab+b²)= (a-b)²= c²≥0, adevarat

as simple as that!