Question

a) 3 supra 8 = 6 supra 3a + 1

b) a + 2 supra 6 = 2 supra 3

c) 7 - 2a supra 6 = 1 supra 2

d) 2a + 1 supra 5 = 7 supra 8

e) 2 + a supra a - 1 = 7 supra 6

Answer 1

a)3/8=6/3a+1
3x(3a+1)=8x6
9a+3=40
9a=40-3
9a=37
a=37/9
b)a+2/6=2/3
(a+2)x3=6x2
3a+6=12
3a=12-6
3a=6
a=6/3
a=2
c)2a+1/5=7/8
(2a+1)x8=5x7
16a+8=35
16a=35-8
16a=27
a=27/16
d)2+a/a-1=7/6
(2+a)x6=(a-1)x7
12+6a=7a-7
12+7=7a-6a
19=1a
a=19