Question

a) 3(x-1) + 1 intregi 1/2 = x + 1/2
b) 3/5(x-2) + x = 1 intregi 1/5 (x+1)
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Answer 1

$a)3(x - 1) + 1 \ \frac{1}{2} = x + \frac{1}{2} = > 3(x - 1) + \frac{1}{2} = x + \frac{1}{2} = > 3x - 3 = x = > 3x - x = 3 = > 2x = 3 = > x = \frac{3}{2}$

$b)\frac{3}{5} (x - 2) + x = 1 \frac{1}{5} (x + 1) = > \frac{3}{5} x - \frac{6}{5} + x = \frac{1}{5} x + \frac{1}{5} = > 3x - 6 + 5x = x + 1 = > 8x - 6 = x + 1 = > 8x - x = 1 + 6 = > 7x = 7 = > x = 1$