Question

A=(4^11*20^20):(2^16*125*2^15*5^7)^2+2^3+1

Answer 1

transform toate puterile in puteri ale lui 2 și 5:
4^11=(2^2)^11=2^22
20^20=(4*5)^20=2^40 * 5^20
125=5^3
A=(2^22*2^40*5^20)/(2^32*5^6*2^30*5^14)+8+1= (2^62*5^20)/ (2^62*5°20)+9=1+9=10
am aplicat regulile de la puteri:
x^a*x^b=x^(a+b)
(x*z)^a=x^a * x^b
(x^a)^b=x^(a*b)