Matematică, întrebare adresată de rosetheo336, 8 ani în urmă

a) { [(-4)²]³×(-4)⁵} : (-4)⁹
b(|-2|×(-2)²×|-8|×(-2)⁴
c) [(-2)³×(-2)²]³:(-512)
Urgent! Dau coroana!​

Răspunsuri la întrebare

Răspuns de QuaTeam
3

a) { [(-4)²]³×(-4)⁵} : (-4)⁹

\frac{\left(\left(-4\right)^2\right)^3\left(-4\right)^5}{\left(-4\right)^9}=16

\left(\left(-4\right)^2\right)^3\left(-4\right)^5=-4^5\times \left(4^2\right)^3

\left(\left(-4\right)^2\right)^3=\left(4^2\right)^3

\left(-4\right)^5\left(4^2\right)^3

\left(-4\right)^5=-4^5

=-\left(4^2\right)^3\times \:4^5

=\frac{-4^5\left(4^2\right)^3}{\left(-4\right)^9}

\left(-4\right)^9=-4^9

=\frac{-4^5\left(4^2\right)^3}{-4^9}

=\frac{\left(4^2\right)^3\times \:4^5}{4^9}

=\frac{\left(4^2\right)^3}{4^{9-5}}

=\frac{\left(4^2\right)^3}{4^4}

\left(4^2\right)^3=4^6

=\frac{4^6}{4^4}

=4^{6-4}

=4^2

=16

b) (|-2|×(-2)²×|-8|×(-2)⁴

\left|-2\right|\left(-2\right)^2\left|-8\right|\left(-2\right)^4

=\left|-2\right|\left(-2\right)^{2+4}\left|-8\right|

=\left|-2\right|\left(-2\right)^6\left|-8\right|

\left(-2\right)^6=64

=\left|-2\right|\times \:64\left|-8\right|

=2\times \:64\left|-8\right|

=2\times \:64\times \:8 = 1024\\

c)  [(-2)³×(-2)²]³:(-512)

\left[\left(-2\right)^3\times \left(-2\right)^2\right]^3\div \left(-512\right)

\left(-2\right)^3\times \left(-2\right)^2

=-8\times \left(-2\right)^2 =-8\times \:4  =-32

=\left(-32\right)^3\div \left(-512\right) =-32768\div \left(-512\right)  =64

Sper că te-am ajutat!

Succes!


rosetheo336: la a) nu cred ca e corect
QuaTeam: de ce?
rosetheo336: poti incerca sa il simplifici
cobuleanuanamaria411: te rugam frumos
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