Question

a=(4^2)^4:2^6:(2^2)3=
b=5^4-(2*11)^2-11^2=
c=(41^2-41*2+1):2^3:5-(2^6-2^5+2^2-2^0)
d=27^30-4*9^44+4^104:2^207-5*(3^44)2
Folosind valoarea pentru a,b,c,d calculeaza:a+b+c+d=...
Va rog ajutati.ma!

Answer 1

a=4^8:2^6:2^6
a=4^8
a=(2^2)^8
a=2^16
b=625-(2^2*11^2)-121
b=625-(4*121)-121
b=625-484-121
b=141-121
b=20
c=(1681-82+1):8:5-(64-32+4-1)
c=1600:8:5-37
c=40-37
c=3
d=(3^3)^30-4*(3^2)^44+(2^2)^104:2^207-5*3^88
d=3^90-4*3^88+2^208:2^207-5*3^88
d=3^90-4*3^88+2-5*3^88
d=3^88(3^2-4+2-5)
d=3^88(9-4+2-5)
d=3^88*2
a+b+c+d=2^16+20+3+3^88*2=2^16+23+3^88*2