Question

a){[4+5•(21615:5)]+31}:100=
b){20+[5•(504:3:2)-20]:40}-15=
c)(1+2+3+..+89+90)+(3+6+9+..+45)=
d)(42+43+44+...+87)-(37+38+39+..+82)=
va rog dau coroana

Answer 1

a) [(4+5×4323)+31]÷100=
[(4+21615)+31]÷100=
(21619+31)÷100=
21650÷100
216 rest 5