Question

a)(4+8+12+...+4000):(2+4+6+...+2000)+(2011+37):2la puterea 10=
b)1+2+3+...+2000=

Answer 1

a) 4 + 8 + 12 + ... + 4000 = 4(1 + 2 + 3 + .... + 1000)

2 + 4 + 6 + ... + 2000 = 2(1 + 2 + 3 + .... + 1000)

2011 + 37 = 2048 = 2^11

Atunci:

(4 + 8 + 12 + ... + 4000) : (2 + 4+ 6 +...+2000) + (2011 + +37) : 2^10 =

= [4 * (1 + 2 + 3 +...+ 1000)] : [(2 * (1 + 2 + 3 + ... + 1000)] + 2^11 : 2^10 =

= 2 + 2 = 4

b) 1 + 2 + 3 + ... + 2000 = (1 + 2000) * 2000 : 2 = 2001 * 1000 = 2001000