Question

a) 402+[1002÷3(100+a)×2]÷14=408

b) 40+90÷[9+48:(a+6)]=46

dau coroana ​

Answer 1

Explicație pas cu pas:

a) 402+[1002÷3(100+a)×2]÷14=408

402+[334(100+a)×2]:14=408

[334(100+a)×2]:14=408-402

334(100+a)×2=6×14. /:2

334(100+a)=42

33400+334a=42

334a=-33358

a=-16679/167

b) 40+90÷[9+48:(a+6)]=46

90:[9+48:(a+6)]=6

9+48:(a+6)×6=90

48:(a+6)=81

81(a+6)=48

a+6=48:81=16/27

a=(16-6×27)/27

a=-146/27