Question

a)48:(2x+10)=6
b)-60:(3x+7)=12
c)72:(5x+6)=-8
d(2x-6):12=5
e)(4x+2):(-7)=10
f)(7x-4):(-5)=-9 dau coroana

Answer 1

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Answer 2

$a) \\ \\ 48 : (2x + 10) = 6 \\ \\ \frac{48}{2x + 10} = 6 \\ \\ \frac{48}{(2x + 5)} = 6 \\ \\ \frac{24}{x + 5} = 6 \\ \\ 24 = 6(x + 5) \\ \\ \frac{24}{6} = x + 5 \\ \\ 4 = x + 5 \\ \\ 4 - 5 = x \\ \\ - 1 = x \\ \\ x = - 1$

$b) \\ \\ - 60 : (3x + 7) = 12 \\ \\ - 60 = 12(3x + 7) \\ \\ - \frac{60}{12} = 3x + 7 \\ \\ - 5 = 3x + 7 \\ \\ - 5 - 7 = 3x \\ \\ - 12 = 3x \\ \\ - \frac{12}{3} = x \\ \\ - 4 = x \\ \\ x = - 4$

$c) \\ \\ 72 : (5x + 6) = - 8 \\ \\ 72 = - 8(5x + 6) \\ \\ - \frac{72}{8} = 5x + 6 \\ \\ - 9 = 5x + 6 \\ \\ - 9 - 6 = 5x \\ \\ - 15 = 5x \\ \\ - \frac{15}{5} = x \\ \\ - 3 = x \\ \\ x = - 3$

$d) \\ \\ (2x - 6) : 12 = 5 \\ \\ \frac{2(x - 3)}{12} = 5 \\ \\ \frac{x - 3}{6} = 5 \\ \\ x - 3 = 5 \times 6 = 30 \\ \\ x = 30 + 3 = 33$

$e) \\ \\ (4x + 2) : ( - 7) = 10 \\ \\ \frac{2(2x + 1)}{ - 7} = 10 \\ \\ - \frac{2(2x + 1)}{ - 7} = 10 \\ \\ - 2(2x + 1) = 10 \times 7 = 70 \\ \\ 2x + 1 = - \frac{70}{2} = - 35 \\ \\ 2x = - 35 - 1 = - 36 \\ \\ x = - \frac{36}{2} = - 18$

$f) \\ \\ (7x - 4) : ( - 5) = - 9 \\ \\ - \frac{7x - 4}{5} = - 9 \\ \\ - 7x + 4 = - 9 \times 5 = - 45 \\ \\ - 7x = - 45 - 4 = - 49 \\ \\ x = \frac{ - 49}{ - 7} = \frac{49}{7} = 7$