Matematică, întrebare adresată de chismaia473, 8 ani în urmă

A) 5*(11,3-2,4*3,5)+11=
B) [13,4+0,5*(147,8-1,25*100)]*10-13,41=
C) 11*(48-12*3,4)+5*[19+4*(8,3-5,4)]-20,3=
D) [21:(2+0,5la puterea a 3 :1,25):10+0,5]:1,5*7,2=
E) [0,2la puterea a 8 *(2:0,2-0,5*20)]:5=
F) {3+0,5*[2,3-0,2*(3,1-5,12:3,2)]}:4=
VA ROG PE FOAIE URGENT


chismaia473: steluta este inmultire

Răspunsuri la întrebare

Răspuns de didina50
4

a) 5×(11,3-2,4×3,5)+11=

=5×(11,3-8,4)+11=

=5×2,9+11=

=14,5+11=

=25,5

b) [14,4+0,5×(147,8-1,25×100)]×10-13,41=

=[14,4+0,5×(147,8-125)]×10-13,41=

=(14,4+0,5×22,8)×10-13,41=

=(14,4+11,4)×10-13,41=

=3×10-13,41=

=30-13,41=

=16,59

c) 11×(48-12×3,4)+5×[19+4×(8,3-5,4)]-20,3=

=11×(48-40,8) +5×(18+4×2,9)-20,3=

=11×8,8+5×(18+11,6)-20,3=

=96,8+5×29,6-20,3=

=96,8+148-20,3=

=51,2-20,3=

=30,9

d) [21:(2+0,5^3:1,25):10+0,5]:1,5×7,2=

=[21:(2+0,125:0,125):10+0,5]:1,5×7,2=

=[21:(2+1):10+0,5]:1,5×7,2=

=(21:3:10+0,5):1,5+7,2=

=(7:10+0,5):1,5+7,2=

=(0,7+0,5):1,5+7,2=

=1,2:1,5+7,2=

=0,8+7,2=

=8

e) [0,2^8×(2:0,2-0,5×20)]:5=

=[0,00000256×(0,4-10)]:5=

=[0,00000256×(-9,6)]:5=

=(-0,000024576):5=

=(-0,0000049152)

f) {3+0,5×[2,3-0,2×(3,1-5,12:3,2)]}:4=

={3+0,5×[2,3-0,2×(3,1-1,6)]}:4=

=[3+0,5×(2,3-0,2×1,5)]:4=

=[3+0,5×(2,3-0,3)]:4=

=(3+0,5×2):4=

=(3+1):4=

=4:4=

=1

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