Question

a=5√12+3√27-9√3
b=√48+2√3-√75
Calculeaza cele doua nr si media lor geometrica!
Va rog este URGENT!

Answer 1

A=5√12+3√27-9√3
3√27=$3* \sqrt{3*3*3}=3*3 \sqrt{3} =9 \sqrt{3}$
5√12=$5*\sqrt{2*2*3}=5*2* \sqrt{3} =10 \sqrt{3}$A=10√3+9√3-9√3
A=10√3b=√48+2√3-√75
$\sqrt{48} = \sqrt{2*2*2*2*3} =4 \sqrt{3}$
$\sqrt{75} = \sqrt{5*5*3}= 5\sqrt{3}$
b=√48+2√3-√75=4√3+2√3-5√3=6√3-5√3=√3
b=√3

A=10√3,b=√3Media geometrica=$\sqrt{10 \sqrt{3} * \sqrt{3} } = \sqrt{10*3} = \sqrt{30}$