Question

a×(57-13×4)=340; (m×2-40)÷23=12; (m-416÷4+2)×5=1980.

Answer 1

A x (57-52)=340
A x 5=340
A=340:5
A=68

(mx2-40)=12 x 23
mx2-40=276
mx2=276+40
mx2=316
m=316:2
m=158

(m-104+2)=1980:5
m-104+2=396
m-104=396-2
m-104=394
m=394+104
m=498

Answer 2

ax(57-13x4)=340
ax(57-52)=340
ax5=340
a=340:5
a=68

(mx2-40):23=12
(mx2-40)=12x23
(mx2-40)=276
mx2=276+40
mx2=316
m=316:2
m=158

(m-416:4+2)x5=1980
( m-106)=1980:5
m-106=396
m=396+106
m=502