Question

A))(6/ 3√2 -2√3)^2=
b))(7/2√2-5√2/8)*4=
c))0,05:10^-2+60/√20-√180+(1/3)^-1=
d))25^-1:0,008-(3√2-4/√2-3,5:2=
e))(3√5-1)(3√5+1):11=
f))2√3*√2+2√6-√30:√5=
g))totul sub un radical 3^2+4^2/9^2+12^2=

Answer 1

a)(6/3√2 -2√3)²=
=(2/√2 -2√3)²=
=(√2 -2√3)²=
=2 -4√6+12=
=14 -4√6

b)(7/2√2-5√2/8)*4=
=14/√2-5√2/2=
=14√2/2-5√2/2=
=9√2/2
 
c)0,05:10⁻²+60/√20-√180+(1/3)⁻¹=
=5/100:1/10²+60/2√5-6√5+3¹=
=5/100×100+30/√5-6√5+3=
=5+30√5/5-6√5+3=
=8+6√5-6√5=8

d)25⁻¹:0,008-(3√2-4/√2-3,5:2)=
=1/25:8/1000-(3√2-4√2/2-1,75)=
=1/25×1000/8-(3√2-2√2-1,75)=
=1/25×125-(√2-1,75)=
=5-√2+1,75=
=6,75-√2

e)(3√5-1)(3√5+1):11=
=(45-1):11=
=44:11=4
 
f)2√3*√2+2√6-√30:√5=
=2√6+2√6-√6=3√6


g)√(3²+4²)/(9²+12²)=
=√(9+16)/(81+144)=
 =√25/225=
 =√1/9=1/3