Question

A(6;8),B(-4;2),O(0;0),M este mijlocul lui (AB).Calculati distanta AB si OM?

Answer 1

AB =
$\sqrt{ {( - 4 - 6)}^{2} + {(2 - 8)}^{2} } = \sqrt{ {( - 10)}^{2} + {( - 6)}^{2} } = \sqrt{100 + 36} = \sqrt{136} = 2 \sqrt{34}$
M = ( (6-4)/2 ; (8+2)/2 ) => M = ( 2/2 ; 10/2) => M = ( 1 ; 5 )

OM =
$\sqrt{ {(1 - 0)}^{2} + {(5 - 0)}^{2}} = \sqrt{ {1}^{2} + {5}^{2} } = \sqrt{1 + 25} = \sqrt{26}$