Question

a )(6+$\sqrt{6}$ ) (3$\sqrt{2}$ +4$\sqrt{3}$) ($\sqrt{3}- \sqrt{2}$ )

b)$( \sqrt[3]{9}+ \sqrt[3]{3}+1) (1- \sqrt[3]{3}$

Answer 1

(6+√6)(3√2+4√3)(√3-2)=(18√2+24√3+3√12+4√18)(√3-2)=(18√2+24√3+6√3+12√2)(√3-2)=(30√2+30√3)(√3-2)=30√6-60√2+30*3-60√3=30(√6-2√2+3-2√3)