Question

a) 7/12+7/16+7/18=?
b)1 intreg si 1/26+2/39+3/13+4/65=?

Answer 1

[tex]a)\frac{7}{12}+\frac{7}{16}+\frac{7}{18}=\\ \frac{84+63+56}{144}=\frac{203}{144}\\ b)1\frac{1}{26}+\frac{2}{39}+\frac{3}{13}+\frac{4}{65}=\\ \frac{27}{26}+\frac{2}{39}+\frac{15+4}{65}=\\ \frac{81+4}{78}+\frac{19}{65}=\\ \frac{85}{78}+\frac{19}{65}=\frac{425+114}{390}=\frac{539}{390}[/tex]

Answer 2

[tex] a)\frac{7}{12}+ \frac{7}{16}+ \frac{7}{18}= 12)_\frac{7}{12}+ 9)_\frac{7}{16}+ 8)_\frac{7}{18}= \frac{84+63+56}{144} = \frac{203}{144} [/tex]

$b)1 \frac{1}{26}+ \frac{2}{39}+ \frac{3}{13} + \frac{4}{65}= 15)_\frac{27}{26}+ 10)_\frac{2}{39}+ 30)_\frac{3}{13} + 6)_\frac{4}{65} = \frac{405+20+90+24}{390} = \frac{539}{390}$