Question

a)(7603:61+877):500+53•11; b)207•9-(19²+3²):74+2296:41;
c)5•230-7•(512:32+2²)+4687:43;
d)[493:17-(128:2²+224:8):22]:27-1.
Vă rog să mă ajutați!!!!!​

Answer 1

Răspuns: Rezolvarea exercițiului e mai jos

Explicație pas cu pas:

$\bf a)~ (7503: 61 + 877): 500 + 53\cdot 11=$

$\bf (123 + 877): 500+ 53\cdot11=$

$\bf 1000: 500+ 53\cdot11=$

$\bf 2 +53\cdot11=$

$\bf 2 +583=$

$\blue{\underline{~\bf 585~}}$

$\bf b)~ 207\cdot9-(19^2-3^2): 74 +2296: 41=$

$\bf 1863-(361+9): 74 +2296: 41=$

$\bf 1863-370: 74 +56=$

$\bf 1863-5 +56=$

$\purple{\underline{~\bf 1914~}}$

$\bf c)~ 5\cdot230 - 7\cdot (512:32 + 2^2) + 4687: 43=$

$\bf 1150-7\cdot (16 + 4) + 109=$

$\bf 1150-7\cdot 20 + 109=$

$\bf 1150-140 + 109=$

$\bf 1010 + 109=$

$\pink{\underline{~\bf 1119~}}$

$\bf d)~ [493: 17- (128: 2^3+ 224:8):22]: 27-1=$

$\bf [493: 17- (128: 8+ 28):22]: 27-1=$

$\bf [29- (16+ 28):22]: 27-1=$

$\bf (29- 44:22): 27-1=$

$\bf (29- 2): 27-1=$

$\bf 27: 27-1=$

$\bf 1-1=$

$\red{\underline{~\bf 0~}}$